Urgent.!!! Multiple if within while loop ksh

UNIX for Beginners Q & A
1

Hi All,

I'm trying to write while loop with multiple if conditions. Each and every if condition with different variables. whenever one if condition fails i have remove the file
from filename and have to pick another file and loop should exit until the last file found in filename. Please help how to write a ksh shell script for that. Below i have given code what i tried

Thanks in advance.!!!

example:
#### here filename contain XXXX_YYYY_ZZZZ_DDD.txt as example
while read filename
#splitting a file without extension
full_filename=$filename
noextension=${full_filename%.*}
extension="${full_filename##*.}"

####assigning a patterns to different variable

echo "$noextension"|awk -F'_' '{ print NF-1 }' > countpattern

##### First fi######
if [ "$countpattern" -eq 5 ] ; then
A=$(echo $noextension|cut -d'_' -f1)
B=$(echo $noextension|cut -d'_' -f2)
C=$(echo $noextension|cut -d'_' -f3)
D=$(echo $noextension|cut -d'_' -f4)
E=$(echo $noextension|cut -d'_' -f5)
fi

####Second If########
if [ ! $extension=txt-a $A=HELP] || [ ! $extension=csv -a ! A =HELP ]
then
UPDATE TABLE ########################
rm full_filename
fi

####third if#####
if [ ! $C = "WE" ]
then
UPDATE TABLE ########################
rm full_filename
fi
2

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3

One way to break a huge logic statement like that into several smaller ones is:

while read filename
do
        REMOVE=0

        if [ ! condition1 ]
        then
                REMOVE=1
        fi


        if [ ! condition2 ]
        then
                REMOVE=1
        fi


        if [ ! condition3 ]
        then
                REMOVE=1
        fi

        if [ "$REMOVE" -eq 1 ]
        then
                remove_filename
        fi
done