Hi
I am trying to write a code like this
echo "enter a type"
read a_type
while [ $a_type != "S" ] || [ "$a_type" != "s" ] || [ "$a_type" != "SR" ] || [ "$a_type" != "sr" ] || [ "$a_type" != "a" ] || [ "$a_type" != "A" ]
do
echo "invalid engine type Please enter correct a_type"
read engine_type < /dev/tty
done
My problem is that even if i give the a_type as the correct one that i have listed above that is S or s so on and so forth it is still entering in the loop and telling invalid a_type
Instead if i give = condition in while it is working fine . That is if i give while [ $a_type = "S" ] then if i give S it is entering and not S it is not entering . But giving = dosent satisfy my code . I have to give not equal to if i want the code to work
Please help
Thanking in advance
is working fine
but how to short cut it say i mean the user can enter S or s A or a or Sr rS like that
writing everything in while makes it cumbersome
Is there any other way
Thanks in advance
To be honest i think you should change your programs logic completely: You enter a character (or word), some values are legal, ALL others are not. You do not need the functionality of a while-loop at all, so why should you use it?
How about the following, which is easily extensible:
print - "enter a value: " ; read value
case value in
[Ss])
print - "You entered an s or an S."
;;
[Nn])
print - "You entered an n or an N."
;;
*)
print - "You entered an illegal value"
;;
esac
This should also be easier to read and to maintain.
If you want to use the code part as a device to process the commandline you could also resort to the getopts-program. Have a look at the manpage for it and if this fits your requirements and you still have problems applying it come back and ask again.