Hi,
I have unix script on solaris 5.10.
I have to verify existence of 3 files in path and sleep for 1 hour.
I have tried for 1 file:
if [ -f /path/filename ]
then
echo " File is found!"
sleep 3600
echo "time delayed"
fi
Please advice
Why not use a cron job that is run every hour and then checks the files?
I don't have any idea about cron job 
Can i use something like :
#!/usr/bin/ksh
if [ -f /path/file1 and -f /path/file2]
then
echo " File is found!"
sleep 300
echo "time delayed"
fi
how about
#!/bin/ksh
until [[ 1 -gt 2 ]]; do # infinite loop
status="found" # default to true
for i in file1 file2 file3; do
if [ ! -f $i ]; then
status="not found" # if one or more of the files doesn't exist set to false
fi
done
echo Files are ${status}.
sleep 5
done
if your requirement is to sleep for a defined time, only if ALL files exist:
in a ksh shell
( [[ -f file1 ]]; [[ -f file2 ]]; [[ -f file3 ]] ) && ( sleep 30;echo all files found ) || echo one or more files not found
Thank you 
It is working
i have create one dir that have 3 files and my following script keep checking those file in every 10 sec
#!/usr/bin/ksh
DD=`date`
while :;
do
if [ -f ./tmp/tmp1.tmp -a -f ./tmp/tmp2.tmp -a -f ./tmp/tmp3.tmp ]; then
echo "File Exist $DD " >> ./log.tmp
else
echo "One of File Not exist $DD" >> ./log.tmp
fi
sleep 10
done
but i guess you need another script to kick of this script so if you even log off your machine it won't affect your script
#!/usr/bin/ksh
nohup ./file_check.ksh &
this script will kick off the file_check.ksh and terminate and it will keep record the log in the nohup.out and log.tmp
I hope this might help you out.
Thanks
Soni