Variable values within for loop

Shell Programming and Scripting
1

Hi All

I am trying to fetch the size of three files into three separate variables within a for loop and am doing something like this:

for i in ATT1 ATT2 ATT3
do
size_$i=`ls -ltr $i | awk '{print $5}'`
echo ${size_$i}
done

but am getting the below error:

ksh[3]: size_ATT1=522:  not found
ksh[3]: size_ATT2=2170:  not found
ksh[3]: size_ATT3=874:  not found

Any idea how to fix the "not found" error?

Thanks in advance

2

Try:

for i in 1 2 3
do
  size=$(ls -l ATT$i | awk '{print $5}')
  echo "${size}"
done

or, since you are using KornShell:

for i in 1 2 3
do
  ls -l ATT$i | read x x x x size x
  echo "${size}"
done
3

I tried both the options but am getting

ksh[3]: ATT1: bad number

The name of each file should get suffixed to the variable being used i.e. size_ATT1 and the echo should return the value stored in the variable as in the size in this case. So the output should be something like:

size_ATT1=522
size_ATT2=2170
size_ATT3=874

and the echo should only return the values:

522
2170
874

Not sure if it can be made to work this way

4

Try using either BASH as shebang or rewrite the shown code to match ksh syntax.
Or, use the array-suggestion from scrutinizer.

Assigning values to a variablename formed by using variables is a complex thing, well, not really, but risky and prone to errors, and should be avoided where possible.
You could write the generated string (all 3 lines of size_ATT{1..3}=...) by writing it to a file, then source it.

hth