I wrote this script
#!/bin/bash
var=`du -sch /var/log/messages;du -sch /var/log/maillog`
echo $var
I am getting result as follows.
# sh my.sh
2.1M /var/log/messages 2.1M total 296K /var/log/maillog 296K total
I need it like below
2.1M /var/log/messages
296K /var/log/maillog
Can anyone help?