how to check
- If variable is declared or not
- If any value if assigned to variable or not.
in UNIX shell script
how to check
in UNIX shell script
read man page on test command
Have a read of your man page of test.
Edit: 116@434 was faster!
hi, i have gone thru it.
One of my file contains variable and its value (A to E )
param.ksh
----------
IF [ $1 = "MYDB" ]
then
export A=123
export B=345
C=789
D=
fi
Now this script i am invoking from other shell scropt
. param.ksh
here, i need to check that all 5 (A,B,C,D,E) variables should be declared and assigned values to it, in order to proceed further. If any one of the variable is not declared or value is not assigned to it. process should stop and exit
use an and function
if [ $A="" -a $B="" -a ... etc ]
then
echo "error"
exit error_code
else
do something...
fi
if [ $A="" ... ] checks if value is NULL
not tested with more than 2 variables but it should work
@metal005 Your script as posted contains syntax and logic errors. Needs to be an OR test and all variables should be quoted because we need to look at empty variables.
Maybe you meant:
# Error if parameter not set
set -u
# Error if parameter empty
if [ -z "$A" -o -z "$B" -o -z "$C" -o -z "$D" -o -z "$E" ]
then
echo "One or more parameters is empty"
exit
fi
ofcourse sorry my bad
it has to an or function...
wassnt thinking clear
your way should work great though... good programming