Variable comparison in 'if' with a string.

Shell Programming and Scripting
1

Hi All,

I want to compare the variable value with string in a shell script.
my code is:

for var in $packsName
do 
 if [ $var -ne 'ABC' || $var -ne 'XYZ' ]
 then
   echo $var
 fi
done

But I am getting error as:

ABC : not found.

Am I going wrong somwhere?
please guide.

Thanks.

2 
for var in $packsName
do 
if [ "$var" != "ABC" -o "$var" != "XYZ" ]
then
echo $var
fi
done

But I don't know if this test is really what you want to have, as it will always return true :wink:

3

What I want is, in all the values for $var, I dont want the statements to be executed for ABC and XYZ.

I tried your solution, but it still prints for ABC and XYZ.
I dont want it to be printed.. :frowning:

4

Try:

for var in $packsName
do 
  if [ "$var" != "ABC" -a "$var" != "XYZ" ]
  then
    echo $var
  fi
done
5

Thanks, -a option worked.

Can you please tell me the difference between -o and -a option?

6

-o means logical OR, while -a is logical AND.