Using sed to put text end of line

Shell Programming and Scripting
1

how to use sed to put .txt end of line..my input file below

file1
make=^bak12^".
DEV=LONG^cmd/usr/bak/ade4^"
.....................................

file 2
make=^and_LONG/bak12^".
DEV=LONG^cmd/usr/bak/ban3^"
..........................................

file 3
....................................
DEV=LONG^cmd/usr/bak/13_2^"
...............................

file 4
...............................
DEV=LONG^cmd/usr/bak/14_2^"
..........................

i want my output file become
file 1
...........
DEV=LONG^cmd/usr/bak/ade4.txt^"
......................

file 2
.................................
DEV=LONG^cmd/usr/bak/ban3.txt^"
..................................

and so on

thanks

2 
echo 'DEV=LONG^cmd/usr/bak/ade4^"' | sed 's#..$#.txt&#'
3

Hi zulabc,

Another way:

$ cat infile
DEV=LONG^cmd/usr/bak/ade4^"
DEV=LONG^cmd/usr/bak/ban3^"
DEV=LONG^cmd/usr/bak/13_2^"
DEV=LONG^cmd/usr/bak/14_2^"
$ sed 's/\(\^\)/.txt\1/2' infile
DEV=LONG^cmd/usr/bak/ade4.txt^"
DEV=LONG^cmd/usr/bak/ban3.txt^"
DEV=LONG^cmd/usr/bak/13_2.txt^"
DEV=LONG^cmd/usr/bak/14_2.txt^"

Regards,
Birei

4

Hi,

echo 'DEV=LONG^cmd/usr/bak/ade4^"' | sed 's#..$#.txt&#'

I would like to know how this sed command will work?

5

take the last 2 characters and prepend them with ".txt".

6

my fault actually my input file is in different file

file 1
.........

DEV=LONG^cmd/usr/bak/ade4^"

................

file 2
...................

DEV=LONG^cmd/usr/bak/ban3^"

......................

and so on

so i want my output file ending with .txt before ^"

7

doesn't the proposed solution work?