using grep in a while loop

Linux and Unix-Like Red Hat
1

Hello everybody,

I have been searching it, but it seems I am unable to find the correct information, that s why I am asking you guys, hoping somebody get an idea.
Here is my problem :

I want a script to loop until a string is identified in a log file.
Here is the script :

 
#!/bin/sh
##Wait for database script to finish
rc=2
while [ ! $rc -eq 0 ]
do
grep "BUILD SUCCESSFUL" /berp001_i1/AMH/database/logs/database_2012-01-31_15-11-45.log
rc="$?"
done

Do you have an idea where is the problem ?

Again thank you and sorry if the answer were outthere.

guyiom

2

Hi guyiom,

I don't understand. What do you want to achieve? Loop until a string in the log file and what?

Regards,
Birei

3

Hello Birai,

Thank you for your interest for my problem.
I want my script to hang in loop until it finds the string in the log, and then the script should continue until its end.
Is it clearer ?

guyiom

4 
while ! grep "BUILD SUCCESSFUL" /berp001_i1/AMH/database/logs/database_2012-01-31_15-11-45.log > /dev/null
do
        sleep 1
done
5

Hello Corona688.

Thank you for your answer, but when I execute the script, I get this error :

"
[amh@berp001 database]$ ./test.sh
-bash: ./test.sh: /bin/sh^M: bad interpreter: No such file or directory
"

Any idea what I am doing wrong ?

Thank you

guyiom

6

You are editing scripts in Microsoft Notepad. This fills your scripts with useless carriage returns, which UNIX will consider part of the filename or command.

Edit them in UNIX instead.