Using find for variable combination of perms

Shell Programming and Scripting
1

Hi,

I'm trying to use find in kshell (AIX) to find all files with perms of
write for other
AND
any execute bit set.

e.g:
r--r-x-w- would qualify
and rw-rw--wx would qualify
but ---rwxr-xr-x wouldn't qualify

So far, I've been trying something like this:

find . -type f -perm -o=w -a \( -perm -u=x -o -perm -g=x -o -perm o=x \) -ls

But this is just giving me files with execute bit set anywhere, but not necessarily files with write for other.

Any help much appreciated thanks, Alan.

2

Can u try this.

 find . -perm -o=w -a \( -perm -u+x -o -perm -g+x -o -perm -o+x \) -ls
3 
find . -type f \( -perm -102 -o -perm -012 -o -perm -003 \) -ls
4

Thanks millan and MadeInGermany, I will try those suggestions tomorrow during the day when I'm connected to a UNIX box again.
(It's 9:35pm here in New Zealand right now).

Will let you know how it goes. Cheers, Alan.

5

Ok, tried both variants suggested above, and, whaddya know, they both worked beautifully.

> find . -perm -o=w -a \( -perm -u+x -o -perm -g+x -o -perm -o+x \) -ls
   93    1 -rw-----wx  1 alanp     staff            970 Sep  6  2011 ./smit.log
   94    1 -rwx----w-  1 alanp     staff            176 Sep  6  2011 ./smit.script

> find . -type f \( -perm -102 -o -perm -012 -o -perm -003 \) -ls      
   93    1 -rw-----wx  1 alanp     staff            970 Sep  6  2011 ./smit.log
   94    1 -rwx----w-  1 alanp     staff            176 Sep  6  2011 ./smit.script

Not found (correctly) were the below
-rwx------ 1 alanp staff 20023 May 18 2012 sudo_check.sh
-rwx------ 1 alanp staff 92808 Dec 08 2011 extract_global.ksh
-rw-----w- 1 root system 2342 Dec 07 2012 wlghost1.txt
-rw-----w- 1 root system 78765 Mar 24 2009 wlghost1_lpp.txt

Thanks again millan and MadeInGermany.

Alan.