using awk to print some columns of a file

Shell Programming and Scripting
1

Hi,
i have a file with content

00:01:20.613 'integer32' 459254
00:01:34.158 459556
00:01:36.626 'integer32' 459255

and i want to print only output as below

00:01:20.613 459254
00:01:34.158 459556
00:01:36.626 459255

i dont want the word 'integer32' which is the second column.

i tried

awk -F" " '$2=='integer32' && $3>0 { print $1,$3 }'  zddd.txt >> zresult.txt

but it does not work.
Please assist

3

For the provided input, try this:

awk '{print $1,$NF}' file
4

thank you, both worked