using awk != parameter

Shell Programming and Scripting
1

Hi all,

I am having the below file log.txt

1 aaa 111 @@@
2 bbb 222 ###
14 ccc 333 $$$

using awk '$1!=1 || $1!=14 {print $1" " $2}' log.txt

gets the below output

1  aaa
2  bbb
14  ccc

any one can sort what the problem is ?

thanks in advance

2

You want "and", not "or". One condition or the other is true even if $1 is 1 or $1 is 14 (sic).

awk '$1!=1 && $1!=14 {print $1" " $2}' log.txt
3

hey thanks era

4

how to sort this output in ascending order

5

Pipe the awk output to sort. Check the man page of sort.