using array

Shell Programming and Scripting
1

hello experts

can u tell me please how i have a text file .
In third field of a file there are names like

abb
asa
asas
asasas
i just want to store the third filed of a file in an array.
and to display the result in a same order using for loop through array
can any one tell me how to do this in the shell script

take care bye

shary

2

What is the field delimiter? The following assumes a comma:

integer i=0
awk 'BEGIN {FS=OFS=","} {print $3}' file.txt | while read item; do
  myarray[$i]=$item
  i=$i+1
done

If the fields are delimited by spaces, just eliminate the BEGIN block:

integer i=0
awk '{print $3}' file.txt | while read item; do
  myarray[$i]=$item
  i=$i+1
done
3

You can loop through the array you created with this:

for x in ${myarray[*]}; do
  print $x
done
4

With bash:

$ cat file
filed1 filed2 field3_1 field4
filed1 filed2 field3_2 field4
filed1 filed2 field3_3 field4
filed1 filed2 field3_4 field4
filed1 filed2 field3_5 field4
filed1 filed2 field3_6 field4
filed1 filed2 field3_7 field4
$ a=($(cut -d" " -f3 file))
$ i=0;until((i>=(${#a}-1)));do echo ${a};((i+=1));done
field3_1
field3_2
field3_3
field3_4
field3_5
field3_6
field3_7

With awk:

awk '{x[NR]=$3}
END{for(i=1;i<=NR;i++)print x}' file
5

This will work with ksh93 also.

6 
eval ` awk ' { printf("arr[%d]=%s\n",NR,$3) } END { printf("tot=%d",NR) }' file `
i=1
while [[ $i -le $tot ]]
do
	echo ${arr[$i]}
	(( i=i+1 ))
done
7

hi experts

thank you so much for your cooperation i really appreciate your quick response.

Regards,
Shary