users per group

Shell Programming and Scripting
1

hi guys

I am trying to display a list of groups and the respective users:

Group1 : user1 user2 user3 ....

the closest thing I get is

echo " "; echo "Group       Users   "; echo " "; cat /etc/group |grep [5-9][0-9][0-9] | grep -v nfs

which I really don't since I want to remove the other stuff like x : and the group ID

something like I wrote before

Group1 : user1 user2 user3 ....
Group2 : user1 user4 user5 ....

thanks a lot

2

You could try this for the secondary groups

awk -F: '/[5-9][0-9][0-9]/{print $1" : "$4}' /etc/group

But note that you have to get primary group info from /etc/passwd.

3

you can try this

cat /etc/group | grep -v "^.*:$" | sed 's/\([a-zA-Z][a-zA-Z]*\):x:[0-9][0-9]*:\(.*\)/\1 : 2/'
4

A method which includes primary groups. Assumes you have the unix "logins" command. Script allows for more than one line in /etc/group for the same group (which can happen).

#!/bin/ksh
awk -F: '{print $1}' /etc/group| sort | uniq |while read GROUP
do
    USERLIST=$( logins -g "${GROUP}" | awk '{print $1}' | sort |tr '\n' ' ' )
    echo "${GROUP} : ${USERLIST}"
done
5

thanks a lot I think this one does what I need :smiley:

awk -F: '/[5-9][0-9][0-9]/{print $1" : "$4}' /etc/group | grep -v nfs