Unix Script with line number at beginning of each line.

Could anybody help me.
I need to create a script that reads a text file from STDIN and prints out the file to STDOUT with line numbers at the beginning of each line.

Thanks.

'man nl'

you could also check sed1liners

here's the relative snippet:

How do I run this on the Unix Terminal?
# count lines (emulates "wc -l")
sed -n '$='

You can also do :

cat -n /path/to/file

Jean-Pierre.

In The terminal. It shows that I do not have a file or directory with that name.
cat -n /path/to/file

Thanks for any help you could give me.

/path/to/file is an example file name not a real file name

A complete filename (example, not real) is /home/mascorro/text.lis
The path is /home/mascorro
the file is named text.lis

Plus vgersh99 gave you the answer

nl <filename of your choice goes here>