Unable to print dynamic arguments in for loop

Hi All,

I want to pass few dynamic arguments to shell script. The number of arguments differ each time I call the script.

I want to print the arguments using the for loop as below. But not working out.

for (( i=1; i<=$#; i++ ))
do
  echo $"($i)"
done

/bin/sh test.sh arg1 arg2 arg3

Any one please help.

for((i=1; i<=${#}; ++i)); do
     echo ${!i}
done