Unable to Print Count

Shell Programming and Scripting
1

Hi All,

I am performing addition of two inetger variables which assigning output to a new variable getting following error.

Check1.sh

#!/bin/ksh
filesrc=/usr/kk/Source1.txt
filetgt=/usr/kk/Source2.txt
 
FINAL_COUNTS= `awk '{n++} END {printf "%012d\n",n}' ${filesrc} ${filetgt}`

echo 'Final Count is:'$FINAL_COUNTS

Below is the output:

 
+ awk {n++} END {printf "%012d\n",n} /usr/kk/Source1.txt /usr/kk/Source2.txt
+ 000000000014
+ FINAL_COUNTS=
./Check1.sh[5]: 000000000014:  not found.
2

Replace space before awk :

#!/bin/ksh
filesrc=/usr/kk/Source1.txt
filetgt=/usr/kk/Source2.txt
 
FINAL_COUNTS=`awk '{n++} END {printf "%012d\n",n}' ${filesrc} ${filetgt}`

echo 'Final Count is:'$FINAL_COUNTS

or add quotes if you wat a space before count in FINAL_COUNTS :

#!/bin/ksh
filesrc=/usr/kk/Source1.txt
filetgt=/usr/kk/Source2.txt
 
FINAL_COUNTS=" `awk '{n++} END {printf "%012d\n",n}' ${filesrc} ${filetgt}`"

echo 'Final Count is:'$FINAL_COUNTS

Jean-Pierre.

1 Like
3

Thanks its worked

4

Wouldn't this suffice?

FINAL_COUNT=`printf "%012d" $(cat $filesrc $filetgt | wc -l)`