unable to pass value to user prompt from calling shell script

Shell Programming and Scripting
1

This is my script structure
main script calls configure script which needs to be run as a different user and the configure script calls my application installation script. the application instruction script prompts the user for a directory which I need to pass from my main or configure script.

main script
{
su - user1 -c "exec "configure.sh""
}
configure script
{
echo -e /u0x/tmp2/ | sudo ./INSTALL -silent
}

where install script prompts the user to enter a path which is what i am passing as /u0x/tmp2.

The problem I am facing is that the install script is not accepting the input that I passed to it.

Any pointers to this will be very useful.

Thanks in advance

2

In what way does it not accept it?

Perhaps the input is coming too soon? ( sleep 1; echo path ) | ./INSTALL

Or perhaps the script actually reads from the terminal, not stdin? Look inside it to see how it prompts for the path. Perhaps there's a way it can be overrided without input at all.

3

The invoked script (install) pauses at that prompt and is designed not to proceed further until it receives input. Here is the code snippet from the install script

    while [ 1 ]
    do
            echo "Enter the path to directory containing RPMs or <abort> to exit!"
            read RPM_DIR;
            [[ "$RPM_DIR" == "abort" ]] && exit 1
             if [ -d $RPM_DIR ] ******proceeds further to continue installing rpms"
      done
4

If all it does is read, then there's no reason "echo asdf | whatever" will not work.

Which is why I suspect there's still more to the script.

5

I just manually executed the script by switching to user 1
echo -e /u0x/tmp2/ | sudo ./INSTALL -silent and the script successfully accepted the input value .

My guess is that the issue occurs due to the way the main script invokes another script and this parameter is not being passed.
su - user1 -c "exec "configure.sh""