Hi, 'm trying to do an exercicise, and one part is:
ls -l $1 | awk '
BEGIN {
max = $5;
}
{
if ($5 > max){
max = $5;
}
}
END {
print "Tamanio mayor fichero = " max; }'
# Imprimimos ahora el menor tama�o de fichero
ls -l $1 | awk '
BEGIN {
min = $5;
}
{
if ($5 < min){
min = $5;
}
}
END {
print "Tamanio menor fichero = " min; }'
Seek the maximum and minimum size of files that are to implement the command ls-l. The problem is that it shows me the right way to screen the most, but not the least, and more turns that I fail to see what could be the problem.
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Thanks.
The command of the BEGIN section executes before any input is read so the value of min is empty, to find the minimum size you can do something like this:
ls -l $1 | awk '
NR==2{
min = $5; next
}
{
if ($5 < min){
min = $5;
}
}
END {print "Tamanio menor fichero = " min; }'