Hi, I need to display the last column value in the below o/p.
sam2 PS 03/10/11 0 441
Unable to get o/p with this awk code
awk -F"[/]+" '{ print $4 }' pwdchk.txt
I need to display 441(in this eg.) and also accept it as a variable to treat it with if condition and take a decision. Requesting help.
---------- Post updated at 08:53 PM ---------- Previous update was at 08:45 PM ----------
Oh! just hit upon an idea
awk -F"[/ ]+" '{ print $7 }' pwdchk.txt
I do get o/p as 441; but is it correct way? Just did on trial and error basis. Please suggest/explain.