Track user log!

ETC Homework & Coursework Questions
1

Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!

  1. The problem statement, all variables and given/known data:
    The task is to measure the density of users that are logged on system. The program
    should check that every 30 sec, but not check older logs than 2 days(24h) and write that into a text file. So the logs shouldn't be older than 2 days. The records of logged users must be saved in a file for today and what was going on yesterday.
    And the time difference MUST be 30 seconds between checkings...

It should look like this:
Time: 11:50:10 Users: 2
Time: 11:50:40 Users: 5

1.file for today Today.txt
2.file for yesterday logs Yesterday.txt

  1. Relevant commands, code, scripts, algorithms:
    ??

  2. The attempts at a solution (include all code and scripts):
    I'm thinking about the function who -Hlrmu and to cat that into a file
    than read how many lines a file has minus the first one.

#!/bin/bash

while true; do
sleep 30
users=$(who -Hlrmu | cat >> record.txt | wc -l record.txt | cut -c1-2)
echo -e "Time: ???? Users:$users\n"

done
exit

I don't know how to measure the time and to separate the files into two,
one for today and one for yesterday.

Am I on the right path? I'm not i know hahaha

  1. Complete Name of School (University), City (State), Country, Name of Professor, and Course Number (Link to Course):
    University of Ljubljana, Ljubljana, Slovenia, Janez Novak, ID63709

Note: Without school/professor/course information, you will be banned if you post here! You must complete the entire template (not just parts of it).

2

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3

Hmm but i must post a homework in a correct forum, and my homework is in a rush, so
i still can post a homework in the Emergency UNIX and Linux Support !! Help Me!! - The UNIX and Linux Forums ???

4

just read the rules and don't use words like "urgent" in your title.

5

Ok i will, can you help me with the problem i have?

---------- Post updated 28-05-10 at 02:03 PM ---------- Previous update was 27-05-10 at 08:18 PM ----------

Does the who -m lists users who are on the system or just me?

would it be better if i used the command users or simply who ?

6

You can use who to get the number of users logged in your system...

who -m will show you "only hostname and user associated with stdin"

man who

Try this:

You'll need to adjust the output redirection and maybe the cron schedule.

7

Aha, what if i use $(users | wc -l)
coz, who returns me on two consoles tty7 and pts/0

How can i separate the files, the Today.txt must contain users who were logged in today
and Yesterday.txt must contain yesterday logs, and i should have no more than 2 days old logs.

Something like if [ $(date +%Y%m%d).log -ge than 48h ]; than delete it?
How can i tell if a file is older than 2 days?

---------- Post updated at 03:58 PM ---------- Previous update was at 02:40 PM ----------

it would be even better if i rewrite from today.txt into yesterday.txt, but only when
24 hours passes and the today.txt will be blank.
What i mean is...i must keep track of the users for 24 h and then rewrite it
to a yesterday.txt file!:slight_smile:

How is that doable???

8 
#! /bin/sh
[ $(date "+%H")-eq 0 ] && (mv path/to/today.txt /path/to/yesterday.txt)
echo "Time: $(date +%T) Users: $(who | wc -l)" >> /path/to/today.txt

Run this script thru crontab every 10 seconds.