to print number one less than actual number

Shell Programming and Scripting
1

suppose we have a file which contains
34
45
56
77
55
66
54
67

so output shud be like
33
44
55
76
54
65
53
66

2

file_no's content are
34
45
56
77
55
66
54
67

tempfile=file_no
for number in `cat $tempfile`
do
number=$((number-1))
echo $number
done

3 
zsh 4.3.4% cat file
34
45
56
77
55
66
54
67
zsh 4.3.4% eval printf "%d\\\n" $(printf "\$((%d-1)) " $(<file))
33
44
55
76
54
65
53
66

or:

zsh 4.3.4% awk '$1=$1-1' file
33
44
55
76
54
65
53
66
4

or you can do something like this

for line in `cat $file`
do
line=`expr $line - 1`
echo $line
done

Thanks
Namish

5

Hey please try this one,

awk ' { printf ("%d\n", $0-1) } ' <<File Name>>