To get the hidden files information only

UNIX Solaris
1

Hi all,

I want to get only hidden files(which are start with '.' or '..') information in a current directory. I tried the below command,

$ find . -name "^." -exec ls -la '{}' \;

but it's not working. Can anyone give me your outputs.

Thanks in advance,
Raghu.

2

ls -la

3

The way to find hidden file is

find . -name ".*"

It will find all files including dot(.) And if you do exec on this ls -l . will print all the files in the directory....

Try:

for i in $(find . -name ".*")
do
   if [[ $i = "." || $i = ".." ]]; then
      continue
   fi
   ls -l $i
done

---------- Post updated at 02:32 PM ---------- Previous update was at 02:32 PM ----------

This will give all the files... not ONLY hidden files.

4

No need for the caret, just use

$ find . -type f -name '.*' -exec ls -l {} \+
5

Thanks for your reply Saga.

But I want output with hidden files only..
ls -la will give us the all files information including hidden files.

You have any clue?

Thanks,
Raghu.

6

-type f did the trick...interesting.