to get the correct value with unsigned int

Applications Programming
1

hi,

Please help me with the following code to get the difference in values.

struct a{
		int b1;
		int c1;
		char d1;
	}

main()
{
	unsigned int b=10;
	unsigned int c;
	c = b - (unsigned int )sizeof(a);
  	printf("%d",c);
}

Here c returns some junk value. How can i get the difference between b and sizeof (a) in a positive value without using abs.

Thanks

2

I modified your program slightly to get it to work:

#include<stdio.h>

struct a {
        int b1;
        int c1;
        char d1;
};

int main() {
        unsigned int b=10;
        unsigned int c;
        c = b - (unsigned int )sizeof(struct a);
        fprintf(stdout,"size of a: %d, size of int: %d, size of char: %d\n",sizeof(struct a),sizeof(int),sizeof(char));
        fprintf(stdout,"%d\n",c);
        return(0);
}

This is the output:

# ./a.out
size of a: 12, size of int: 4, size of char: 1
-2

Now I agree that for two ints and one char, the size should be 4+4+1=9, but memory allocation is not done a single byte at a time. This is system dependent.

3

Hi ,
the solution given above is right but i want to correct at one point.
c = b - (unsigned int )sizeof(struct a);
printf("%d\n",c); will print -2 because any struct occupy the memory in chunk of words. and for linux word is 4 bytes. so for char it occupies 4 bytes give one byte to char and pad the rest 3 bytes so sizeof(struct a) gives 12 as size
:slight_smile: