TO break a line

Shell Programming and Scripting
1

hi All,
Have a doubt in ksh..Am not familiar with arrays but i have tried out a script..
plzzzzz correct me with the script

My i/p File is:

(DESCRIPTION =
(ADDRESS_LIST =
(ADDRESS =
(PROTOCOL = TCP)
(Host = 192.168.2.2)
(Port = 1525)
)
)
(CONNECT_DATA = (SID = TESTDB1)
)
)

(DESCRIPTION =
(ADDRESS_LIST =
(ADDRESS =
(PROTOCOL = TCP)
(Host = 192.168.2.4)
(Port = 1525)
)
)
(CONNECT_DATA = (SID = TESTDB2)

And My script is:

while read line
do
i=0

a[$i]=`grep "Host" |cut -d" " -f3 |tr -d ')'`
echo ${a[$i]}
i=`expr $i + 1`
done < File Name

Am trying to get the value of host and assign it to an array

My O/p is

192.168.2.2 192.168.2.4

But i need the o/p to be:

a[0]=192.168.2.2

a[1]=192.168.2.4

2 
awk -F" = " '/Host/ { arr[i++] = substr($2, 0, length($2) - 1) }END{ for ( i in arr ) { print i, arr } }' filename
3

change the echo statement to

echo "${a[$i]} \n"
4

Thank Matrix!!!!!!!!!!

But how to store the value in an array

Like

Host[0]=192.168.2.2
Host[1]=192.168.2.4

5

its already in the array named 'arr'

thats what I have printed in the END block of awk.

Are you looking for displaying it in the format posted ?

6

Yes Am looking for the Format which i have given in the o/p

7

With zsh:

zsh 4.3.4 % host=(${$(grep -F Host file)//[^0-9.]/})
zsh 4.3.4 % print $host[1]
192.168.2.2
zsh 4.3.4 % print $host[2]
192.168.2.4

With bash:

bash 3.2.13(1) $ while read;do 
> [[ "$REPLY" == *Host* ]]&&host=($host ${REPLY//[^0-9.]/})
> done<file
bash 3.2.13(1) $ echo ${host[0]}
192.168.2.2
bash 3.2.13(1) $ echo ${host[1]}
192.168.2.4
8

Just modify the print clause in the awk command to,

awk -F" = " '/Host/ { arr[i++] = substr($2, 0, length($2) - 1) }END{ for ( i in arr ) { printf "Host[%d]=%s\n", i, arr } }' filename