test wordcount

Shell Programming and Scripting
1

Hello

I want to run this test:

If wordcount of a command is 0 then echo XXXX else echo YYYYY

if [ `cat /tmp/foobar.txt | awk '{print $2}' | grep database | grep -v `df -k |grep /dev/dsk | awk '{print $6}'` | wc -l` != 0 ]; then echo "all devices are created on RAID10"; else echo "Some devices are created on non-RAID10"; fi

I receive this message
-bash: command substitution: line 1: syntax error near unexpected token `|'
-bash: command substitution: line 1: ` | wc -l'
Usage: grep -hblcnsviw pattern file . . .
awk: can't open !=
-bash: [: missing `]'
Some devices are created on non-RAID10

Can you please advise?

bash$ cat /tmp/foobar.txt | awk '{print $2}' | grep database | grep -v `df -k |grep /dev/dsk | awk '{print $6}'` | wc -l
34

2 
if [ `awk '{print $2}' /tmp/foobar.txt | grep database | grep -v 'df -k' |grep '/dev/dsk' | awk '{print $6}' | wc -l` -ne 0 ]; then echo "all devices are created on RAID10"; else echo "Some devices are created on non-RAID10"; fi

Too many grep-s, awk-s and cat-s - could be simplified with a single 'awk'

3

df -k |grep /dev/dsk | awk '{print $6}'

should return

/zeus1

In your example, you are using grep '/dev/dsk'
while I want to do grep -v /zeus1 (the latter is obtained from the first command I put)

thanks for your support

4

my guess is that you'll need to escape the inner backticks.. try it out and see if it works..

in my opinion it makes the code, well, a little difficult to understand and maintain by an average person, so i'd recommend so break it up a little.