i have this program in bash shell:
#!/bin/bash
array=(20 20 20 20 20)
i=0
j=0
awk '/%/ {print $3}' try.txt|
while (read s)
arr[$i]=$s
i=`expr $i + 1`
echo "$i"
end
how can i convert this into c shell?
That's not the way to do it in bash:
while read s; do
Why are you using an external command for integer arithmetic in bash?
i=$(( $i + 1 ))
Don't.
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