substitute variable in bash

Shell Programming and Scripting
1

hi all,

Assume that i a having the following three lines in an executable file

#/bin/bash
a=Tue
Tue=1

When i give echo $a the value should be 1, how to do this. Your suggestions please.

Thanks in advance,
Anish

2

You should initiate the Tue Variable before the a variable.

In your script, when you assign the Tue variable to a it has no value.
Your script should be like this :

#/bin/bash
Tue=1
a=Tue
3

And since variable 'a' does not hold value as $Tue we add another $ in the below echo statement to print Tue's value.

eval echo \$$a
4

Hi dude ,

The code which you posted is not working

echo $a given means it shows tue

5

But:

#/bin/bash
Tue=1
a=${!Tue}