Subsitution in file

Shell Programming and Scripting
1

I am calling oracle from a shell script and basically retrieving a
line into a variable called command which contains a command which is like
rwrun60 userid=$DATABASE_USER par_start_date =$PAR_START_DATE .....
when I try to execute this command using `echo $command`
It does not subsitute the values of the various parameters
like $DATABASE_USER which are defined in the file.
Can anybody help me
Regards,
Saurabh

2

Try:

exec $command

:wink:

3

try:

echo -e "$variable"

or

printf "$variable\n"

4

You can use this :

userid=${DATABASE_USER}
par_start_date =${PAR_START_DATE}

for more information : http://www.cs.princeton.edu/~jlk/kornshell/doc/man88.html

${parameter }
The shell reads all the characters from ${ to the matching } as part of the same word even if it contains braces or metacharacters. The value, if any, of the parameter is substituted. The braces are required when parameter is followed by a letter, digit, or underscore that is not to be interpreted as part of its name or when a variable is subscripted. If parameter is one or more digits then it is a positional parameter. A positional parameter of more than one digit must be enclosed in braces. If parameter is * or @, then all the positional parameters, starting with $1, are substituted (separated by a field separator character). If an array identifier with subscript * or @ is used, then the value for each of the elements is substituted (separated by a field separator character).

I hope help you

Witt