String starting with blank space

Shell Programming and Scripting
1

[quotes]
Dear Masters,

Need your help for this small query.
I am trying to get all the strings that starts with a blank space as output.
Limitation is , it should be done only through AWK.

Input will be:

aa
 _1bbb
 c-ccc
ddd
 eeeee
 ff

Output should be:

_1bbb
 c-ccc
 eeee
 ff
2

bad quoting ...

3 
awk '/^ /' filename
4

print all lines starting with blank :

awk '/^[[:blank:]]/' infile

print all lines except those starting with blank:

awk '!/^[[:blank:]]/' infile
5

Thanks to ALL for your reply.
For reply:1 -> I'm getting the output as:

awk '/^ /' infile
 _1bbb  yes
 c-ccc  yes
 eeeee  yes
 ff  yes

But when I tried something as below, inorder to do conditional manipulation based on the value of $1, I didn't get any output.

>awk '{ if($1 ~ /^  /) {print $0}}' infile

For reply:2 -> I'm not getting the desired output which I think may be because [:blank:] searches for tab space.

>awk '/^[[:blank:]]/' infile ---> no output
>awk '!/^[[:blank:]]/' infile
aa  no
 _1bbb  yes
 c-ccc  yes
ddd  no
 eeeee  yes
 ff  yes

FYI, my infile have below contents:

>cat infile
aa  no
 _1bbb  yes
 c-ccc  yes
ddd  no
 eeeee  yes
 ff  yes

Regards,

6

This works correctly for me

$ awk '/^[[:blank:]]/' file
 _1bbb  yes
 c-ccc  yes
 eeeee  yes
 ff  yes

Perhaps you need to use nawk or gawk.