Hi,
temp="/usr=25,/usr/lib=12"
How to get only dir names with out values.
I tried like below but no use.
tmp=${temp##*,}
echo $tmp
o/p:
/usr/lib=12
expected o/p:
/usr /usr/lib ---> in array
In bash, try:
IFS=, read -a ARR <<< "$temp"
printf "%s\n" "${ARR[@]%=*}"
In awk you could do:
awk -F\= '{print $1}' INfile >> OUTfile
I don't understand how this awk code is going to help solve OP's problem.
Another approach to get required values into an indexed array would be:
temp="/usr=25,/usr/lib=12"
typeset -a arr
typeset -i idx
for key in ${temp/,/ }
do
arr[$idx]="${key/=*/}"
(( idx++ ))
done
printf "%s\n" "${arr[@]}"
Hi,
Thanks for the solution.
When I try to apply the code to read a file. I am not getting the proper output.
readfile
temp=/usr=25,/usr/lib=12
bin=12
etc=45
lib=12:6
output should be
echo $temp
/usr /usr/lib
echo $bin
12
echo $etc
45
echo $lib
12:6
Can we get like above.
Those are different requirements than what is in post #1. Please specify more clearly what it is you are trying to achieve..
Hi,
I tried this logic to read a file and get t he values but no use.
function read_params()
{
until [ -z "$1" ]
do
if [ `expr index "$1" =` != 0 ] ; then
tmp=$1
typeset -a arr
typeset -i idx
parameter=${tmp%%=*}
for key in ${tmp/,/ }
do
arr[$idx]="${key/=*/}"
value="${arr[@]}"
(( idx++ ))
eval $parameter=\"$value\"
done
fi
shift
done
}
function main()
{
read_params `cat readfile.txt`
echo $temp
echo $bin
echo $lib
}
main
readfile.txt
temp=/usr=25,/usr/lib=12
bin=12
etc=45
lib=12:6
output:
/usr /usr/lib
12
12:6
please let me know what went wrong in my code
---------- Post updated at 02:45 AM ---------- Previous update was at 01:33 AM ----------
Hi,
Please find the above post for more details.
Please always state your problem clearly. By changing the requirement you are simply wasting the time of the member who tried to help you.
I would suggest using Associative Arrays for this requirement:
#!/bin/bash
typeset -A arr
while read line
do
var="${line%%=*}"
for key in ${line//,/ }
do
val="${key#${var}=}"
val="${val%=*}"
if [ ! -z arr["$var"] ]
then
arr["$var"]="${arr["$var"]} $val"
else
arr["$var"]="$val"
fi
done
done < file
for k in "${!arr[@]}"
do
printf "%s %s\n" "$k" "${arr["$k"]}"
done
Input:
$ cat file
temp=/usr=25,/usr/lib=12
bin=12
etc=45
lib=12:6
Output:
$ ./script.bash
bin 12
etc 45
lib 12:6
temp /usr /usr/lib
Hi,
Not able to get the output properly.
#!/bin/bash
typeset -a arr
while read line
do
var="${line%%=*}"
for key in ${line//,/ }
do
val="${key#${var}=}"
val="${val%=*}"
if [ ! -z arr["$var"] ]
then
arr["$var"]="${arr["$var"]} $val"
else
arr["$var"]="$val"
fi
done
done < file
for k in "${!arr[@]}"
do
printf "%s %s\n" "$k" "${arr["$k"]}"
done
file:
temp=/usr=25,/usr/lib=12
bin=12
etc=45
lib=12:6
output:
# sh readfile.sh
0 /usr /usr/lib 12 45 12:6
Can we write the code in multilple function like below and need to use "eval" command to get the parameter name and respective value from the main function.
Overall I have to get the correct output for the below code.
#! /bin/sh
typeset -a arr
read_params()
{
#while read line
until [ -z "$1" ]
do
if [ `expr index "$1" =` != 0 ] ; then
var="${1%%=*}"
for key in ${1//,/ }
do
val="${key#${var}=}"
val="${val%=*}"
if [ ! -z arr["$var"] ]
then
arr["$var"]="${arr["$var"]} $val"
else
arr["$var"]="$val"
fi
done
eval $var=\"${arr["$var"]}\"
fi
shift
done
#done < $1
for k in "${!arr[@]}"
do
printf "%s %s\n" "$k" "${arr["$k"]}"
done
}
main()
{
read_params `cat file`
echo "$temp and $lib"
}
main
Expected output:
# sh readfile.sh
/usr /usr/lib and 12:6
Please let me know what would be the mistake I did in the above code.
I said associative arrays not indexed arrays:
typeset -A arr
Correct but the below error caused to modified it as "-a".
This feature is available only on certain systems.
I tested this code on below system and version and it works:
$ bash --version
GNU bash, version 3.2.25(1)-release (x86_64-redhat-linux-gnu)
Copyright (C) 2005 Free Software Foundation, Inc.
But it will not work on below system and version:
$ bash --version
GNU bash, version 3.2.51(1)-release (sparc-sun-solaris2.10)
Copyright (C) 2007 Free Software Foundation, Inc.
Bash 3 does not have associative arrays. That is a bash 4 feature. If it happens to work in a particular version of bash 3 it probably is an undocumented feature and should not be relied upon.
As an alternative one could use ksh93 instead, which is a fast and advanced shell that also knows associative arrays.
Hi,
Observed a strange behavior from the above code.
arr["$var"]="${arr["$var"]} $val"
above snippet will have the space in front of the text.
It requires if the string having two variable(Ex: temp=/usr=25,/usr/lib=12) but it is not required when the string contains only a variable(Ex: etc=45).
value=/bin/$etc
resulting value="/bin/ 45" it should be value="/bin/45".
The space has to avoid when we do "eval"
eval $var=\"${arr["$var"]}\"
Is this possible, please let me know the way.