string manipulation in arguments

Shell Programming and Scripting
1

Hi all, I have a requirement where I am taking the first argument as argument name and storing the second argument in argument name as value.
Thanks to ppl here, i learnt to do it.:stuck_out_tongue:

while ( $1 != "" )               
    	set arg = $1
        shift
        set val = "$1"
        echo "set $arg=$val" > temp_file && source temp_file
        shift
end

Now,the format of my argument has changed, which is instead of argument name (say "./script arg1 1"), I am taking "./script -arg1 1",
I still need to save the "1" value in arg1, which is generated once i give "-arg1" as an argument.

is there anyway i can directly generate "arg1" instead of "-arg1" as my variable?

Please advice.

2

Hi,

Try:

set arg = ${1#-}

Regards,
Birei

3

I found a partial solution

while ( $1 != "" )               
    	set arg = "`echo $1 | sed '/-/s// /g'`"
        echo $arg
        shift
        set val = "$1"
         echo "set $arg = $val" > temp_file && source temp_file
        shift  
end

but still I am getting an error:

me@linux: csh -x ./test -a 1 -b 2
while ( -a !=  )
set arg = `echo -a | sed '/-/s// /g'`
echo -a
sed /-/s// /g
echo a
a
shift
set val = 1
echo ------------------------------------------------------arg ==  a
------------------------------------------------------arg ==  a
echo ------------------------------------------------------val == 1
------------------------------------------------------val == 1
echo set  a = 1
source temp_file
set a = 1
shift
echo you created parameter (  a ) with value ( 1 )
you created parameter (  a ) with value ( 1 )
end
while ( -b !=  )
while: Missing file name.

---------- Post updated at 02:59 PM ---------- Previous update was at 02:53 PM ----------

Hey birei

I am afraid your syntax is not working.
I am scripting in c shell, i guess it is not supported by csh.

---------- Post updated at 03:40 PM ---------- Previous update was at 02:59 PM ----------

This is the solution

while ( "$1" != "" )               
    	set arg = "`echo $1 | sed '/-/s// /g'`"
        echo $arg
        shift
        set val = "$1"
         echo "set $arg = $val" > temp_file && source temp_file
        shift  
end