String Comparison in Shell script

UNIX Solaris
1

I Have a script which gets the status of oracle database and if the status is READ WRITE ..it should echo "db is up " else "db is down"

Here is the code

if [ "$status" = "READ WRITE" ]
then
  echo "db up"
else
  echo "db down"
fi
done;

The script is giving me out put "db down" even thoug the value of variable status is READ WRITE.

2

Try "==" and see if the space between READ and WRITE is indeed a space, not a tab or something.

3

Tried putting "==" no progress. There is a space between "READ WRITE"

4

before 'if' put:

echo "x${status}x"
echo "xREAD WRITEx"

and see if they are the same.

5

Hello Friend,

I think you reply was in the right direction to fix the problem in the code..This is what i am geting after echoing those 2 values

 
x{
READ WRITE}x
 
xREAD WRITEx

That means my variable $status has READ WRITE with some space on the front..thats why its unable to compare..can you please tell me how can i get rid of those spaces

Thankyou somuch for you help

6

See:

echo -e "bla\nbla" | tr -d '\n'

The following:

tr -d '\n'

will remove any newlines from input.

7

I tried this..
what happens is if i run it on the command prompt (outside) script it works fine..But in the script its not removing spaces

 
echo -e "   READ WRITE"|tr -d '\n'
READ WRITE

 
new_status=`echo -e "$status"|tr -s '\n'`
echo "x{$new_status}x"
echo "xREAD WRITEx"
 
x{-e READ WRITE}x
xREAD WRITEx

---------- Post updated at 12:08 PM ---------- Previous update was at 12:05 PM ----------

Buddy,

I removed the -e and it works wonders...Gr8 help i was struggling with this since morning :b: