String capture from ip file

Shell Programming and Scripting
1

Dear All

From below mention input file I want op file as mention. Kindly help.

IP file:

"BSCGNR4_IPA17_C" 329 140119 0717 RXOCF-105 KJO001_BASC_NG   AC FAULTY DG ON DOOR OPEN

Needed OP:

140119 0717 KJO001_BASC_NG   AC FAULTY DG ON DOOR OPEN

Note that string mark in red as variable in length. IE no of alarm may be vary.

THANKS.

Regards
Jaydeep

2

Try:

awk '{printf $3" "$4" "$6" "; for (i=7;i<=NF;i++) printf $i" ";printf "\n"}' input
3

OR try this

$ echo '"BSCGNR4_IPA17_C" 329 140119 0717 RXOCF-105 KJO001_BASC_NG   AC FAULTY DG ON DOOR OPEN' | \
awk '{$1 = $2 = $5 = ""; $0 = $0; $1 = $1}1'

140119 0717 KJO001_BASC_NG AC FAULTY DG ON DOOR OPEN

use following with your input file

$ awk '{$1 = $2 = $5 = ""; $0 = $0; $1 = $1}1' file
4

This might then work too:

awk 'sub(".*" $5, $3 FS $4)' file

@OP: Do you know what is the format of the file? How are the fields separated?