Storing output into a variable

Shell Programming and Scripting
1

My script below seems to be choking because I need the the output of the find command to be stored as a variable that can then be called by used lower in the script.

#!/bin/bash
cd "/resumes_to_be_completed"
var1=find . -mmin -1 -type f \( -name "*.doc" -o -name "*.docx" \)
snd="notification@domain.com"
recp="myemail@domain.com"


while inotifywait -e create /resumes_to_be_completed; 
     do sleep 10; 
     sudo chmod -R 777 /resumes_to_be_completed/; 
     cat $var1 | uuencode $var1 | sendmail -F "New Resumes" -f $snd $recp ; done

I run the script and it appears fine until it is triggered.

user@resumes:/scripts# ./new_resumes.sh
Setting up watches.
Watches established.
/resumes_to_be_completed/ CREATE foo.doc
uuencode: invalid option -- 'i'
Try `uuencode --help' for more information.
cat: invalid option -- 'm'
Try `cat --help' for more information.

As you can see its erroring out at the uuencodeportion and that appears to be because the output of the find command isnt being stored.

2

var1 really needs to be the name of a temporary file. Environment variables are not suitable for storing lists of files. Your "find" in not running at all, the environment variable $var1 just contains the command.

# For example:
var1=/tmp/mytemporaryfilename.txt
find . -mmin -1 -type f \( -name "*.doc" -o -name "*.docx" \) > ${var1}

Now $var1 is the name of a file, cat and uuencode should not error.
Personally I don't know about "inotifywait" and have not used "sendmail" in this manner.