Store values in an Array

Shell Programming and Scripting
1

Hi all.

Well, I have the next code:

I need to make an array with the values I have in the bucle, but just don't get it...

Question is, how can I store in an array that values, and how can I display them with echo?

2

Still working in it, but dont get to save the values :frowning:

3 
awk -F: '{
for(i=1; i<=NF; i++)
   b=$i
}' tmpid

OR

awk -F: '{
  split($0, b, FS)
}' tmpid
4

There are a lot of threads regarding this item, search for arrays awk.

Regards

5

vgersh99,

I tried that before, but when I write echo ${b[1]} then I get a blank.

Why this happen?

Franklin52,

I'll be more careful from now on. Sorry.

6

'echo' is a shell command. 'b' is your awk array.

awk -F: '{
for(i=1; i<=NF; i++) 
   b=$i

for(j=1; j<=i; j++)
   printf("j->[%d] b[%d]->[%s]\n", j, j, b[j])
}' tmpid
7

vgersh99,

Im new in the unix world. So now I understand what you told me before.

So, the variables I set within awk, can't be used in shell later?

I mean, I created an array named "b" with "x" elements. That variable is exclusive within awk, isn't it?

8

partially correct - see below.

correct.

Look at this piece of code:

#!/bin/ksh

file='tmpid'
typeset -i i=0

while read input
do
  IFS=:; set -A arr ${input}
  while (( i < ${#arr[@]} ))
  do
    echo "arr[$i]=${arr[$i]}"
    i=$(( $ + 1 ))
  done
  ((i=0))
done < "${file}"

and also here:

#!/bin/ksh

a='one:two::four'

IFS=':' ;set -A arr ${a}

len=${#arr[@]}

typeset -i i=0
while (( i < len ))
do
   echo "arr[$i] ==> ${arr[$i]}"
   i=$(( $i + 1 ))
done

As suggested, use the Search function of these forums to find related threads.

9

Many thanks, you've provided me a great help.

Next question I have, I will search for it first.

Again, many thanks for the tips.