Start all scripts in a directory

Shell Programming and Scripting
1

Good morning.

I have a tricky one here for me. Hope somebody can help.
I am looking for a way to take a single script in a directory and use it to fire all scripts within a subdirectory.

For example.
Lets say I have the following in /lcl/prd/apps

file1.sh
file2.sh
file3.sh
file4.sh
file5.sh

Now lets say that the fire.sh script should execute all scripts within /lcl/prd/apps

So if I was to run fire.sh it should then execute any scripts it finds in /lcl/prd/apps which would be...
file1.sh
file2.sh
file3.sh
file4.sh
file5.sh

So in a nut shell I need to find a way to run a script in a directory that in return runs all the scripts in a subdirectory at once.

Plus we may add or take away scripts at times.
Any ideas?

Thanks!

2 
#!/bin/ksh
# usage: thisscript.sh [directory name]
directory=$1
find $directory -name '*.sh' |
while read filename
do
     nohup $filename 2&>1  > ${filename}.log &
done
wait

This runs all of the *.sh scripts in a directory simultaneously, then waits until they have all finished.

3

Thanks. I was just able to do this also...

cd $Master_Directory
list=`ls *.sh`
for script in $list
do
./$script
done