sorting from several files for a specific data

Shell Programming and Scripting
1

Please assist:

I have several files and all of the files have the same data format like following:
All I need to get item next to "name" field and the "address" field from each file which has only 8 characters in "name" field.

so the output should be:

ams00ark(spcae)10.1.1.12
ams01ark(spcae) 10.1.1.12
per01adp(spcae) 10.1.1.12

start item
name ams00ark
on_off 1
group various
suppress Y
auto_delete N
read_s 123456
write_s 5897856
address 10.1.1.12
terminal 362
icmp_v 5
grade 0
auto_pro 0
time_key_status 0
e-s_ 0
criteria_level 0
end node

start item
name ams01ark
on_off 1
group various
suppress Y
auto_delete N
read_s 123456
write_s 5897856
address 10.1.1.12
terminal 362
icmp_v 5
grade 0
auto_pro 0
time_key_status 0
e-s_ 0
criteria_level 0
end node

start item
name prt00amsten
on_off 1
group various
suppress Y
auto_delete N
read_s 123456
write_s 5897856
address 10.1.1.12
terminal 362
icmp_v 5
grade 0
auto_pro 0
time_key_status 0
e-s_ 0
criteria_level 0
end node

start item
name per01adp
on_off 1
group various
suppress Y
auto_delete N
read_s 123456
write_s 5897856
address 10.1.1.12
terminal 362
icmp_v 5
grade 0
auto_pro 0
time_key_status 0
e-s_ 0
criteria_level 0
end node

Thank you

2

for i in * ;do echo "" ; cat $i| egrep -i 'name|address' | awk '{print $2}' | tr -s '\n' ' '; echo ""; done

or

#!/bin/sh

for i in * ;do
        echo ""
        cat $i| egrep -i 'name|address' | awk '{print $2}' | tr -s '\n' ' '
        echo ""
done
3 
nawk '{
if($1=="name" && length($2)==8)
	t=$2
if($1=="name" && length($2)!=8)
	t=""
if(t!="" && $1=="address")
	print t"  "$2
}' file
4

The last code is pretty good, since I have multiple files how do I integrate the code, should I put wilcard * , since all of the filename starts with ipcheck. Also in I realized that there are two address field and I need to get address starts with 10.x.x.x.x

Thanks,