Sort alphabetically, then numerically

Greetings - I'm not necessarily new to bash scripting - I'm probably between beginner and intermediate, but I have something that I just cannot figure out after many attempts to find it. I have a file that is merely a list of many files, with their respective paths, and a branch path (ClearCase) that they live on. For instance, here is an example of this file:

/vobs/vob/path/to/where/the/file/is/foo.txt@@/main/int/dev/9
/vobs/vob/path/to/where/the/file/is/foo.txt@@/main/int/dev/11
/vobs/vob/path/to/where/the/file/is/foo.txt@@/main/int/dev/10
 

As you can see, there are 3 instances of a file with 3 different versions depicted. Well, I need it sorted to where the end number is in order.
"sort -n" and "sort" doesn't work. The results are:

/vobs/vob/path/to/where/the/file/is/foo.txt@@/main/int/dev/10
/vobs/vob/path/to/where/the/file/is/foo.txt@@/main/int/dev/11
/vobs/vob/path/to/where/the/file/is/foo.txt@@/main/int/dev/9
 

I need it to have the result like this:

/vobs/vob/path/to/where/the/file/is/foo.txt@@/main/int/dev/9
/vobs/vob/path/to/where/the/file/is/foo.txt@@/main/int/dev/10
/vobs/vob/path/to/where/the/file/is/foo.txt@@/main/int/dev/11

How do you do that??? :wall:

nawk -F/ '{print $NF, $0}' myFile | sort -k1n,1 | cut -d ' ' -f2-
 
sort -n -t"/" -k 14  input_file
sed 's#/\([^/]*\)$#|\1#' infile | sort -t\| -k1,1 -k2,2n | sed 's#|#/#'

Thank you kindly, and all other peoples' responses! It worked well! My sincere apologies for not using code tags - lesson learned. Thanks all again! :b:

---------- Post updated at 11:13 AM ---------- Previous update was at 11:12 AM ----------

Forgot to mention that nawk package must be missing, however awk seemed to work just fine. Does it really matter?

if it works - it doesn't :wink: