[Solved] Output on one line

Shell Programming and Scripting
1

A simple question, but i am finding it diffcult to find the answer.

Can you please tell me how i can get the output of two line on one.

I am aware i need to enter \ something, but no sure which charcter, can you advice.

CODE

for i in `cat LDN_HOSTS_190813 | grep -i LDN | awk '{print $1}' | sort -u `
        do
        echo "$i" ; bpimagelist -client $i -d 08/14/2013 18:00:00 -U | egrep -vi "Expires|-" | awk '  { if($5 > 1000000) print $0} ' | awk 'NR==1{print $1,$2,$5,$10,$11}'

Output currerntly

algomd01
08/16/2013 20:23 1577925 LDN_WAT_UX_DEV
allocd01
allocp01
08/18/2013 23:50 2575795 LDN_CAM_UX_PRD
apmapp01

Output required

algomd01    08/16/2013 20:23 1577925 LDN_WAT_UX_DEV
allocd01
allocp01      08/18/2013 23:50 2575795 LDN_CAM_UX_PRD
apmapp01
2

For awk i think you can use

printf ("%s", $0)

instead of

print $0

Hope it helps.

3 
for i in `cat LDN_HOSTS_190813 | grep -i LDN | awk '{print $1}' | sort -u `        do        echo "$i `bpimagelist -client $i -d 08/14/2013 18:00:00 -U | egrep -vi "Expires|-" | awk '  { if($5 > 1000000) print $0} ' | awk 'NR==1{print $1,$2,$5,$10,$11}'`"
4

Sorry did not work... Same output as before capitanui and prasperl

5

Please try the below given code in your shell..just to want to see the outcome

echo "I am `whoami`!"
6

# echo "I am `whoami`!"
I am root!

---------- Post updated at 01:00 PM ---------- Previous update was at 12:57 PM ----------

adsdbi01.zit.commerzbank.com\c
algomd01.zit.commerzbank.com\c
08/16/2013 20:23 1577925 LDN_WAT_UX_DEV

7

Thats good..My suggestion was also on the same logic...I guess your "$i" itself has a \n
...My suggestions

for i in `cat LDN_HOSTS_190813 | grep -i LDN | awk '{print $1}' | sort -u `
        do
        echo -n "$i"
echo  "`bpimagelist -client $i -d 08/14/2013 18:00:00 -U | egrep -vi "Expires|-" | awk '  { if($5 > 1000000) print $0} '`"

Or

for i in `cat LDN_HOSTS_190813 | grep -i LDN | awk '{print $1}' | sort -u `
        do
        var1=`echo "$i" | tr -d '\n'`
var2=`bpimagelist -client $i -d 08/14/2013 18:00:00 -U | egrep -vi "Expires|-" | awk '  { if($5 > 1000000) print $0} '`"
echo "$var1 $var2"
8

Thanks that has worked.....