[Solved] Finding the next line when a pattern matches

Shell Programming and Scripting
1

Hi I have a file like this

Record 182: Rejected
  No Data found
Record 196: Rejected
  File Not Found
Record 202: Rejected
  Invalid argument
Record 212: Rejected
  Bad data

My requirement is to search for the value "Record" and if found, then return the next line of it.

So, from the above file
If I grep for Record, I should be getting
No Data found
File Not Found
Invalid argument
Bad data

2 
$ awk '/Record/{getline;print}' infile

---------- Post updated at 12:06 PM ---------- Previous update was at 11:59 AM ----------

in sed ..

$ sed -n '/Record/{n;p;}' infile
3 
 
perl -lne 'if (/Record/){$_= <> ;print}' Input
4

Thanks a lot for the reply,problem solved