[Solved] Error in script while counting processes

Shell Programming and Scripting
1

Hi all,

Below is a script I'm writing and giving me error:

#!/usr/bin/sh
if [ ps -ef|grep dw.sap|wc -l -gt 17 ]; then
       echo "Success!"
else
       echo "Failure!"
fi

Normally if I do

ps -ef|grep dw.sap|wc -l

it gives me output of 18. So my script checks if it's greater than 17 it echoes success else failure

Please suggest how to correct this.

regards.

2

Hello,

Could you please try the following and let us know.

if [[ `ps -ef|grep dw.sap|wc -l` -gt 17 ]]; then
        echo "Success!"
else
        echo "Failure!"
fi

Thanks,
R. Singh

1 Like
3

Hi Ravinder,

Thanks. It works fine now.

regards.

4 
#!/usr/bin/sh
if [ $(ps -ef|grep dw.sap|wc -l) -gt 17 ]; then
       echo "Success!"
else
       echo "Failure!"
fi
5

Use -c with grep instead of wc -l

#!/usr/bin/sh
if [ $( ps -ef | grep -c dw.sap ) -gt 17 ]; then
       echo "Success!"
else
       echo "Failure!"
fi
6

The following are more precise perhaps (you didn't provide a ps output)

$( ps -ef | grep -c 'dw[.]sap' )

$( ps -ef | grep -wc 'dw[.]sap' )
1 Like