[Solved] Argument list with awk

Shell Programming and Scripting
1

Hello,

I want to execute remote command with ssh.
For exemple, i have a variable

SERVERS=lpar1,lpar2,lpar3

I want to execute some commands like:

ssh -q lpar1 ls /
ssh -q lpar2 ls /
ssh -q lpar3 ls /

Can you help me with awk command ?

Thank you :slight_smile:

2

What have you tried?

3

Hello,

Following may help you in same.

 SERVERS=lpar1,lpar2,lpar3
 Actual_SERVERS=`echo $SERVERS | sed 's/,/ /g'`
 set -A array_SERVERS $Actual_SERVERS
 for a in ${array_SERVERS[@]}
 do
 echo "ssh -q " $a "ls /"
 done

Output will be as follows.

ssh -q  lpar1 ls /
ssh -q  lpar2 ls /
ssh -q  lpar3 ls /

Thanks,
R. Singh

4

It's good !!!
It is possible to do it with awk function ?

Thank you very much

5

Hello,

here is the same as requested.

echo "lpar1,lpar2,lpar3" | awk -F"\," '{for(i=1;i<=NF;i++) {print "ssh -q " $i " ls /"}}'

Output will be as follows.

ssh -q lpar1 ls /
ssh -q lpar2 ls /
ssh -q lpar3 ls /

Thanks,
R. Singh

6

Thank you it's good :b:

7

I don't know why you requested for a solution based on awk! I think it is an overkill when you can do it simply in shell:

SERVERS=lpar1,lpar2,lpar3

for host in ${SERVERS//,/ }
do
        ssh -q $host "ls /"
done