Simple question about charecter count

UNIX for Beginners Q & A
1

Hi, I have collection of letters in a column such as:

AA5678
AA9873434
..
..

I am trying to find the number of charecters in each.

"echo "AA5678"|wc -c

   7---------------->   why does it give 7 instead of 6?
2

It's counting the final line feed as well.

3

how do i avoid the line feed to give the correct value?

4

That depends on how you present the values - in a file? in a variable? echo ing a constant? Mayhap you just subtract one?

5

Hi kvosu...

This might explain the reason:
OSX 10.14.3, default bash terminal.

Last login: Mon May  6 08:56:48 on console
AMIGA:amiga~> echo "" | wc -c
       1
AMIGA:amiga~> echo "123456" | wc -c
       7
AMIGA:amiga~> printf "" | wc -c
       0
AMIGA:amiga~> printf "123456" | wc -c
       6
AMIGA:amiga~> _
6

Deleted.
Double post by me.

7

awk does not consider the RS=\n=(line feed) character:

echo "AA5678" | awk '{print length}'
6

In case you have a shell variable, the ${#var} gives the length:

var="AA5678"
echo ${#var}
6