Show result only if number is greater then

Shell Programming and Scripting
1

Hello all
Im trying to write one liner that will show me results only if the result of the expression is greater then 0
For example:
I do :

find . -name "*.dsp" | xargs grep -c SecurityHandler 
the result are : 
 ./foo/blah/a.dsp:0
./foo/blah1/b.dsp:1
./foo/blah2/c.dsp:2
./foo/blah3/d.dsp:0

Now I like to print only dsp's that the word " SecurityHandler" is more then 0
How can it be done?

2 
find . -name "*.dsp" | xargs grep -c SecurityHandler  | awk ' !/:0/ { print }'