If i do below command in unix prompt which static values (ie 27..97), it is working fine and gives desired output
>ls -d $WORKDIR/batch/somefilename_{27..97}.* 2>/dev/null
somefilename_27.sometxt
somefilename_28.sometxt
somefilename_29.sometxt
..
somefilename_97.sometxt
But if i want to include variables or pass arguments to regular expression then its giving me error "ls: cannot access /home/work/batch/somefilename_{27..96}.*: No such file or directory". But thats not true bec file is present but somehow with variables regex is not working.
>segStart="27"
>segEnd="96"
>myvar="$segStart..$segEnd"
>echo $segStart
27
>echo $segEnd
96
>echo $myvar
27..96
ls -d $WORKDIR/batch/somefilename_{$myvar}.*
"ls: cannot access /home/work/batch/somefilename_{27..96}.*: No such file or directory"
>array=($(ls -d $WORKDIR/batch/somefilename_$myvar.* 2>/dev/null))
>len=${#array[*]}
>echo $len
0
Can someone please advise here why the regular expression is not working when using ls and {..} with variables?
Note: I am trying to store all the directory names in an array whose directory name is between two integer number
for eg there are 1-100 dir available with name file_1.some file_2.some file_3.some .. file_100.some.
If user wants to get directory from 47 till 97, then i want to read that value, store them and pass it in above ls command.
If you have any other alternative that will also help.
Millions thanks in advance guys!
