Shell Scripting: Copy Files with Today's date

Shell Programming and Scripting
1

I was wondering the best way about finding files that were created today and copy them to a directory (grep ?). There can be multiple files for todays date or none. I am looking to copy all of the .lis files for todays date. I may need to modify the filename to include todays date but for the time being I just want to find the files that were created today and copy them to a directory.

Data:

-rw-rw-rw-   1 user  user     1697 Nov 24 09:57 file_8885724.lis
-rw-rw-rw-   1 user  user      103 Nov 24 09:57 file_8885724.log
-rw-rw-rw-   1 user  user     1696 Nov 25 09:58 file_8885728.lis
-rw-rw-rw-   1 user  user      537 Nov 25 09:58 file_8885728.log
-rw-rw-rw-   1 user  user     1700 Nov 25 09:58 file_8885730.lis
-rw-rw-rw-   1 user  user     2663 Nov 25 09:58 file_8885730.log
-rw-rw-rw-   1 user  user     1700 Nov 25 09:59 file_8885731.lis
-rw-rw-rw-   1 user  user      967 Nov 25 09:59 file_8885731.log
-rw-rw-rw-   1 user  user     1700 Nov 25 09:59 file_8885732.lis
-rw-rw-rw-   1 user  user     1817 Nov 25 10:00 file_8885732.log
-rw-rw-rw-   1 user  user     1700 Nov 26 10:00 file_8885739.lis
-rw-rw-rw-   1 user  user      529 Nov 26 10:00 file_8885739.log
-rw-rw-rw-   1 user  user     1693 Nov 26 10:00 file_8885743.lis
-rw-rw-rw-   1 user  user      103 Nov 26 10:00 file_8885743.log
-rw-rw-rw-   1 user  user     1697 Nov 26 10:01 file_8885744.lis
-rw-rw-rw-   1 user  user      103 Nov 26 10:01 file_8885744.log
-rw-rw-rw-   1 user  user     1697 Nov 26 10:01 file_8885751.lis
-rw-rw-rw-   1 user  user      103 Nov 26 10:01 file_8885751.log

Script:

#!/bin/bash
#copy files
cd $1
#I need a loop that will copy the files with todays date
scp $2 $3
#end of loop

Any help would be appreciated. Also, if you provide working code then that would be even better.

2 
find /path/to/folder -name '*.lis' -mtime 0 | while read FILE
do
        echo "Found file $FILE"
done
3

example:

#!/bin/bash
 
dt=$(date +"%b %d")
dtm=$(date +".%b_%d")
 
from_dir=some_dir
to_dir=other_dir
 
cd $from_dir || exit
 
for fl in *.lis
do
  ls -l $fl 2>/dev/null | grep " $dt " && {
    mv "$fl" $to_dir/"$fl$dtm" || exit
  }
done
5

I get the error mentioned below when I try this:

find /path/to/file -name 'file_*.lis' -daystart -mtime 0
 
 
find: bad option -daystart
find: [-H | -L] path-list predicate-list

Any ideas?
Thanks!

6

Your version of find doesn't have the GNU -daystart extension.

Well, there's always the touch trick. Create a file of an exact timestamp, then find all files newer than it.

 # Today's month, day, and year, with all-zeroes for midnight in 24-hour time
touch -t $(date +"%Y%m%d0000") /tmp/$$
find /path/to/folder -name 'file_*.lis' -newer /tmp/$$ |
while read FILE
do
        echo "$FILE was modified today"
done

rm -f /tmp/$$