Shell Script- Need Help Please

Hi guys, we all know that the above script will display "message 1" if and only if it encounters used space value exactly equal to 70%, i would like to display "message 1" with condition equal to or Greater then 70% (=>70%).

I tryed all i know..not sure where i should edit the script..It does not seems to be simple as it looks. is there any other simple way of doing this.

Please Help Me...

Play around with something like this:

#!/usr/bin/ksh

Threshold1=70

df -k | awk -v var="$Threshold1" 'int($4) >= var {print "Diskspace of "$1 " is: "$4}'

Excellent !! Thank You ... it worked....

df -k | awk '{ if($5>75) { print "Diskspace of "$6 " is: "$5} }'