Sequential execution of job in cron

Shell Programming and Scripting
1

Hi

I have a file say xyz.sh, whose contents are as follows :

***************************
#! /bin/ksh
set -x

. /a.sh

. /b.sh

. /c.sh
*****************************
Now will this execute all the three process simultaneously or sequentially?
If it will process simultaneously, is there any way to make it excecute sequentially.

Thanks in advance

Pankaj

2

It should execute sequentially as per the above logic.

3

Hi

Thanks a lot

Suppose above code is wrapped in a file called all.sh , I have another sh script ( reject.sh ) which is dependent on all.sh.

reject.sh should only be fired if all.sh has finished successfully. In case of any error in all.sh , the dependent job ( reject.sh ) must be suspended and a warning mail should be sent. Can u please provide the code whic fullfills these conditions.

Regards

Pankaj

4

Suppose your all.sh is as follows:

#!/bin/sh
if cp "$1" "$1.bak"
then
     exit   
else
    echo "bkedit quitting: can't make backup?" 1>&2
    exit 1
fi

And here is a wrapper script:

. /all.sh
if [[ $? -eq 0 ]]; then
    . /reject.sh
else
    mail abc@abc.com
fi

Regards,
Tayyab