Sequence generator

Shell Programming and Scripting
1

Thanks Guys

This really helped

2

I don't know how many numbers you want to generate, but here is an example for 789-800:

a="00789"
l=${#a}
while [ $a -le 800 ]; do printf "%0${l}d\n" $(( a++ )); done
3

You should probably post your script first, but...

 echo '00789' | awk '{printf("%05d\n", $1+1)}'
4

Thanks guys . This really helped . Thanks a lot .

5

Why did you remove the contents of the original post? Now no one will know what was this code's purpose...

6

bash has a builtin that is a sequence generator:
play with this:

echo {00800..00900}
echo {1,2,3}
echo {1,2,3}{1,2,3}
echo {A..Z}

So,

for i in  {nn..mm} 
do
   # do something with i;
   echo $i
done